Two guns on a battleship simultaneously fires two shells with same speed at enemy ships. If the shells follow the parabolic trajectories as shown, which ship will get hit first ?
As A is having more maximum height it will have more vertical speed uy. So A will take more time than A.
So, ship B will be hit first.
A particle is fired with velocity u making an angle θ with the horizontal. What is the change in velocity when it is at the highest point :
At the highest point of its trajectory, the vertical component of the velocity becomes zero, while the horizontal component remains unchanged.
- Initial velocity: \( u \)
- Horizontal component: \( u_x = u \cos \theta \)
- Vertical component: \( u_y = u \sin \theta \)
At the highest point:
- Vertical velocity: \( u_y = 0 \)
- Horizontal velocity: \( u_x = u \cos \theta \)
The change in velocity is only in the vertical direction, from \( u \sin \theta \) to 0.
So, the change in velocity is:
\[
\Delta v = u \sin \theta
\]
Thus, the change in velocity is \( u \sin \theta \).