Electromagnetic Induction - NEET Physics Chapterwise MCQs & PYQs

NEET Electromagnetic Induction MCQs & PYQs

Question 91:

easy

Assertion (A): Only a change of magnetic flux with time, will maintain an induced current in the coil.


Reason (R): The presence of a large magnetic flux will maintain an induced current in the coil.


 

Assertion (A) is true based on Faraday's Law, which states that induced current is generated only by a change in magnetic flux. Reason (R) is false because a constant magnetic flux, regardless of its magnitude, does not induce a current.

Question 92:

easy

Assertion (A): The mutual inductance of two coils is doubled if the self-inductance of the primary and secondary coil is doubled.


Reason (R): Mutual inductance \(M \propto \sqrt{L_1 L_2}\).


 

The mutual inductance is given by \(M = k \sqrt{L_1 L_2}\). If \(L_1\) and \(L_2\) are doubled, the new mutual inductance becomes \(M' = k \sqrt{(2L_1)(2L_2)} = 2k \sqrt{L_1 L_2} = 2M\). Thus, (A) is true and (R) correctly explains (A).

Question 93:

easy

Assertion (A): If a charged particle is released from rest in a time varying magnetic field, it moves in a circle.


Reason (R): In a time varying magnetic field, conservative electric field is induced.


 

Assertion (A) is false; a charged particle released from rest experiences no magnetic force (\(F_B = q(v \times B)\)). While an induced electric field exists, it does not necessarily cause circular motion. Reason (R) is false; a time-varying magnetic field induces a non-conservative electric field.

Question 94:

easy

Assertion (A): A system cannot have mutual inductance without having self inductance.


Reason (R): If mutual inductance of system is zero, its self-inductance must be zero.


 

Assertion (A) is true, as mutual inductance \(M\) depends on the self-inductances \(L_1\) and \(L_2\) (\(M \le \sqrt{L_1 L_2}\)). Reason (R) is false; if two coils are perfectly uncoupled (\(k=0\)), their mutual inductance is zero, but their self-inductances \(L_1\) and \(L_2\) can still be non-zero.

Question 95:

easy

Assertion (A): At any instant, if the current through an inductor is zero, then the induced emf may not be zero.


Reason (R): An inductor tends to keep the flux constant.


 

Assertion (A) is true: The induced EMF is \(emf = -L \frac{dI}{dt}\). Even if \(I=0\) instantaneously, \(frac{dI}{dt}\) can be non-zero (e.g., during oscillation or switching). Reason (R) is true, describing Lenz's law. However, R is not the correct explanation for A, as A focuses on instantaneous values of \(I\) and \(frac{dI}{dt}\).

Question 96:

moderate

Which among the following unit represents henry?

From induced emf \(e = L \frac{di}{dt}\), we have \(L = \frac{e dt}{di}\). Thus, the unit of inductance (henry) is equivalent to \(\frac{\text{Volt-second}}{\text{Ampere}}\).

Question 97:

easy

Induced emf produced in a coil of area \(A\) rotating with angular velocity \(\omega\) in a magnetic field \(B\) is equal to \[\frac{\sqrt{3}BA\omega}{2}\], when the angle between the area vector of the coil and direction of magnetic field is

The induced emf is given by \(e = BA\omega \sin\theta\). Given \(e = \frac{\sqrt{3}}{2}BA\omega\), we have \(\sin\theta = \frac{\sqrt{3}}{2}\), which yields \(\theta = \frac{\pi}{3}\).

Question 98:

moderate

A transformer connected to \(220\text{ V}\) mains is used to light a bulb of rating \(50\text{ W}\) and \(110\text{ V}\). If the primary current is \(\frac{1}{4}\text{ A}\), the efficiency of the transformer nearly is

Efficiency \(\eta = \frac{P_{\text{out}}}{P_{\text{in}}} \times 100% = \frac{50}{220 \times 1/4} \times 100% = \frac{50}{55} \times 100% \approx 91%\).

Question 99:

moderate

Two circular coils one of small radius \(r\) and other of larger radius \(R\) (\(r \ll R\)) are placed co-axially with centres coinciding. The mutual inductance of the arrangement is

The magnetic field at the center of the outer coil of radius \(R\) carrying current \(I\) is \(B = \frac{\mu_0 I}{2R}\). The flux through the inner coil of radius \(r\) is \(\Phi = B \cdot (\pi r^2) = \frac{\mu_0 \pi r^2 I}{2R}\). Thus, \(M = \frac{\Phi}{I} = \frac{\mu_0 \pi r^2}{2R}\).

Question 100:

easy

27. Among which the magnetic susceptibility does not depend on the temperature: (2001)

Diamagnetism is an intrinsic property arising from the orbital motion of electrons and does not involve the alignment of permanent atomic dipoles against thermal agitation. Hence, its susceptibility is independent of temperature.