Self Induction: Practice Problem & Solution

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Self Induction. Understanding the underlying formula is key to arriving at the correct answer below:

From induced emf \(e = L \frac{di}{dt}\), we have \(L = \frac{e dt}{di}\). Thus, the unit of inductance (henry) is equivalent to \(\frac{\text{Volt-second}}{\text{Ampere}}\).