Nuclear Binding Energy per Nucleon – Rankers Physics

Nucleus: Practice Problem & Solution

Assertion (A): Nuclear binding energy per nucleon is in the \( {}^{8}_{4}\text{Be} > {}^{7}_{3}\text{Li} > {}^{4}_{2}\text{He} \). Reason (R): Binding energy per nucleon increases linearly with difference in number of neutrons and protons.  
(1) Both (A) & (R) are true and the (R) is the correct explanation of the (A)
(2) Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(3) (A) is true but (R) is false
(4) Both (A) and (R) are false

Solution Explained:

To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:

Assertion (A) is false; \( {}^{4}_{2}\text{He} \) has a significantly higher binding energy per nucleon than \( {}^{7}_{3}\text{Li} \) and particularly unstable \( {}^{8}_{4}\text{Be} \). Reason (R) is false; binding energy per nucleon does not increase linearly with the N-P difference. Both (A) and (R) are false.

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