Rankers Physics

Nucleus: Practice Problem & Solution

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is: (2010 Mains)
23.6 MeV
2.2 MeV
28.0 MeV
30.2 MeV

Solution Explained:

To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:

Binding energy of two deuterium nuclei = $ 2 \times (2 \times 1.1) = 4.4 $ MeV. Binding energy of the helium nucleus = $ 4 \times 7.0 = 28.0 $ MeV. Energy released = Final BE - Initial BE = $ 28.0 - 4.4 = 23.6 $ MeV.

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