Atomic Structure: Practice Problem & Solution
An electron jumps from orbit \(n = 4\) to \(n = 3\) in hydrogen atom. Wavelength of the emitted radiation is (\(R\) is Rydberg’s constant)
Solution Explained:
To solve this problem, we apply the core principles of Atomic Structure. Understanding the underlying formula is key to arriving at the correct answer below:
Using Rydberg's formula, \(\frac{1}{\lambda} = R \left(\frac{1}{n_1^2} - \frac{1}{n_2^2}\right)\). Substituting \(n_1 = 3\) and \(n_2 = 4\) gives \(\frac{1}{\lambda} = R \left(\frac{1}{9} - \frac{1}{16}\right) = \frac{7R}{144}\). Hence, \(\lambda = \frac{144}{7R}\).
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