Nucleus: Practice Problem & Solution
For the given reaction, the particle X is:n$^{11}_{6}C \rightarrow ^{11}_{5}B + \beta^+ + X$ (2000)
Solution Explained:
To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:
In $\beta^+$ (positron) decay, a proton is converted into a neutron, releasing a positron ($e^+$ or $\beta^+$) and an electron neutrino ($\nu$) to conserve lepton number. Hence, particle X is a neutrino.
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