Atomic Structure: Practice Problem & Solution
The ionisation potential of hydrogen is 13.6 V. The energy required to remove an electron from the third orbit of hydrogen is
Solution Explained:
To solve this problem, we apply the core principles of Atomic Structure. Understanding the underlying formula is key to arriving at the correct answer below:
The energy of an electron in the \(n\)-th orbit of hydrogen is given by \(E_n = -frac{13.6}{n^2}\text{ eV}\). For \(n=3\), \(E_3 = -frac{13.6}{9} = -1.51\text{ eV}\). Thus, the energy required to remove it is 1.51 eV.
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