Atomic Structure: Practice Problem & Solution
Assertion (A): In a Bohr's atom, frequency of revolution of an electron in its orbit is same as frequency of spectral line, for transition between large quantum numbers. Reason (R): As Principal quantum number increases in a Bohr's atom, energy gap between the energy levels decreases.
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Atomic Structure. Understanding the underlying formula is key to arriving at the correct answer below:
Assertion (A) is true due to the correspondence principle where for large \(n\), \(f_{\text{rev}} \propto 1/n^3\) and \(f_{\text{spectral}} \propto 1/n^3\).
Reason (R) is true because \(E_n \propto -1/n^2\), so \(Delta E = |E_{n+1} - E_n| \propto 1/n^3\). Reason (R) correctly explains why the spectral lines become closer, aligning with the classical revolution frequency for large \(n\).
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