Rankers Physics

Nucleus: Practice Problem & Solution

In the given nuclear reaction, the element X is : n$^{22}_{11}Na \rightarrow X + e^+ + \nu$ (2022)
$^{22}_{12}Mg$
$^{22}_{11}Na$
$^{23}_{10}Ne$
$^{22}_{10}Ne$

Solution Explained:

To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:

This is a positron ($e^+$) emission process, where a proton converts into a neutron. The atomic number $Z$ decreases by 1, and the mass number $A$ remains unchanged. Final $Z = 11 - 1 = 10$, and $A = 22$. The resulting nucleus is $^{22}_{10}Ne$.

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