Photoelectric Effects and deBroglie Equation: Practice Problem & Solution
28. When photons of energy $h\nu$ fall on an aluminum plate (of work function $E_0$ ), photoelectrons of maximum kinetic energy K are ejected. If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be: (2006)
Solution Explained:
To solve this problem, we apply the core principles of Photoelectric Effects and deBroglie Equation. Understanding the underlying formula is key to arriving at the correct answer below:
From Einstein's photoelectric equation, the initial maximum kinetic energy is $K = h\nu - E_0$ . When the frequency is doubled, the new incident energy is $2h\nu$ . The new maximum kinetic energy is $K' = 2h\nu - E_0$ . This can be rewritten as $K' = h\nu + (h\nu - E_0) = h\nu + K$ .
Leave a Reply