Nucleus: Practice Problem & Solution
If the nuclear radius of $^{27}Al$ is 3.6 Fermi, the approximate nuclear radius of $^{64}Cu$ in Fermi is: (2012 Pre)
Solution Explained:
To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:
The nuclear radius follows the relation $R \propto A^{1/3}$. Therefore, $R_{Cu} / R_{Al} = (64 / 27)^{1/3} = 4 / 3$. $R_{Cu} = (4/3) \times 3.6 = 4.8 Fermi$.
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