Rankers Physics

Nucleus: Practice Problem & Solution

The mass number of He is 4 and that of sulphur is 32. The radius of sulphur nucleus is larger than that of helium by the factor of (1995)
4
2
8
$\sqrt{8}$

Solution Explained:

To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:

The radius of a nucleus is proportional to the cube root of its mass number ($R \propto A^{1/3}$). The ratio $R_S / R_{He} = (32 / 4)^{1/3} = (8)^{1/3} = 2$. Therefore, the radius is larger by a factor of 2.

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