Rankers Physics

Photoelectric Effects and deBroglie Equation: Practice Problem & Solution

The momentum of a photon of energy $1 MeV$ in $kg m/s$ will be (2006)
$5 \times 10^{-22}$
$0.33 \times 10^6$
$7 \times 10^{-24}$
$10^{-22}$

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Photoelectric Effects and deBroglie Equation. Understanding the underlying formula is key to arriving at the correct answer below:

Momentum of a photon is $p = \frac{E}{c}$. Energy $E = 1 MeV = 10^6 \times 1.6 \times 10^{-19} J = 1.6 \times 10^{-13} J$. $p = \frac{1.6 \times 10^{-13}}{3 \times 10^8} \approx 5.33 \times 10^{-22} kg m/s$.

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