Photoelectric Effects and deBroglie Equation: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Photoelectric Effects and deBroglie Equation. Understanding the underlying formula is key to arriving at the correct answer below:

Energy of incident photon is $E = \frac{12400}{3000} eV = 4.13 eV$. Maximum kinetic energy is $K_{max} = E - \phi = 4.13 eV - 1 eV = 3.13 eV$. In joules, $K_{max} = 3.13 \times 1.6 \times 10^{-19} J \approx 5 \times 10^{-19} J$. Using $K_{max} = \frac{1}{2}mv^2$, we get $v = \sqrt{\frac{2 \times 5 \times 10^{-19}}{9.1 \times 10^{-31}}} \approx 10^6 m/s$.