Atomic Structure: Practice Problem & Solution
The energy of the ground electronic state of hydrogen atom is $-13.6 eV$. The energy of the first excited state will be (1997)
Solution Explained:
To solve this problem, we apply the core principles of Atomic Structure. Understanding the underlying formula is key to arriving at the correct answer below:
The energy of the nth state is given by $E_n = \frac{-13.6}{n^2} eV$. The first excited state corresponds to $n=2$. Therefore, $E_2 = \frac{-13.6}{2^2} = -3.4 eV$.
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