Rankers Physics

Atomic Structure: Practice Problem & Solution

The energy of the ground electronic state of hydrogen atom is $-13.6 eV$. The energy of the first excited state will be (1997)
$-27.2 eV$
$-52.4 eV$
$-3.4 eV$
$-6.8 eV$

Solution Explained:

To solve this problem, we apply the core principles of Atomic Structure. Understanding the underlying formula is key to arriving at the correct answer below:

The energy of the nth state is given by $E_n = \frac{-13.6}{n^2} eV$. The first excited state corresponds to $n=2$. Therefore, $E_2 = \frac{-13.6}{2^2} = -3.4 eV$.

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