Projectile from Height: Practice Problem & Solution
If a body A of mass M is thrown with velocity \(v\) at an angle \(30^\circ\) to the horizontal and another body B of same mass is thrown with same speed at an angle of \(60^\circ\) to the horizontal, the ratio of range of A and B will be :
Solution Explained:
To solve this problem, we apply the core principles of Projectile from Height. Understanding the underlying formula is key to arriving at the correct answer below:
Horizontal range is given by \(R = \frac{u^2 \sin(2\theta)}{g}\). For complementary projection angles \(\theta\) and \(90^\circ - \theta\) (like \(30^\circ\) and \(60^\circ\)), the horizontal ranges are equal. Thus, the ratio of range is \(1 : 1\).
Leave a Reply