1. Distance and Displacement: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of 1. Distance and Displacement. Understanding the underlying formula is key to arriving at the correct answer below:

The area under a velocity-time graph indeed represents displacement, considering areas above the time axis as positive and below as negative, which is a vector sum.

Displacement is a vector quantity, meaning it has both magnitude and direction. This vector nature directly explains why the signed area (vector sum) under the velocity-time graph yields displacement.

Both (A) and (R) are true, and (R) correctly explains (A).