Fractional change in gravity with depth – Rankers Physics

Acceleration Due to Gravity and its variation: Practice Problem & Solution

The fractional change in acceleration due to gravity on surface of earth (g) when the body is taken to a depth h from the surface of earth, is (where R = radius of Earth)
\(1 - \frac{h}{R}\)
\(\frac{h}{R}\)
\(1 - \frac{2h}{R}\)
\(\frac{2h}{R}\)

Solution Explained:

To solve this problem, we apply the core principles of Acceleration Due to Gravity and its variation. Understanding the underlying formula is key to arriving at the correct answer below:

The acceleration due to gravity at depth \(h\) is \(g_d = g\left(1 - \frac{h}{R}\right)\). The change in gravity is \(\Delta g = g - g_d = g\frac{h}{R}\). Thus, the fractional change \(\frac{\Delta g}{g}\) is \(\frac{h}{R}\).

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