Acceleration Due to Gravity and its variation: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Acceleration Due to Gravity and its variation. Understanding the underlying formula is key to arriving at the correct answer below:

Assertion (A): The effective gravity is given by \(g' = g - Romega^2cos^2lambda\). If \(omega = 0\), then \(g' = g\). This causes \(g\) to increase everywhere except at poles (where \(coslambda = 0\)). So (A) is true.nReason (R): Due to rotation and equatorial bulge, \(g\) is maximum at poles and minimum at the equator. So (R) is true.n(R) correctly explains (A) as the effect of rotation explains the variation.