Rankers Physics

Electric Field: Practice Problem & Solution

The charge per unit length of the four quadrant of the ring is 2λ , – 2λ , λ and -λ respectively. The electric field at the centre is Electric Field diagram: The charge per unit length of the four
-\frac{\lambda}{2\pi\varepsilon_{0}R}\hat{i}
\frac{\lambda}{2\pi\varepsilon_{0}R}\hat{j}
\frac{\sqrt{2}\lambda}{4\pi\varepsilon_{0}R}\hat{i}
None

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