Rankers Physics

Electric Field: Practice Problem & Solution

A thin semi-circular ring of radius r has a positive charge q distributed uniformly over it. The net field \overrightarrow{E} at the centre O is : Electric Field diagram: A thin semi-circular ring of radius r has
-\frac{q}{2\pi^{2}\varepsilon_{0}r^{2}}\hat{j}
\frac{q}{2\pi^{2}\varepsilon_{0}r^{2}}\hat{j}
\frac{q}{4\pi^{2}\varepsilon_{0}r^{2}}\hat{j}
-\frac{q}{4\pi^{2}\varepsilon_{0}r^{2}}\hat{j}

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Similar Practice Questions

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1. Find the electric field due to a circular arc of radius R and charge / length λ at the origin. The arc is in xy plane and extends from θ = π/3 to θ = π w .r.t.x-axis .  
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