Coulomb's Law: Practice Problem & Solution
6. The unit of permittivity of free space $\epsilon_0$ is: (2004)
Solution Explained:
To solve this problem, we apply the core principles of Coulomb's Law. Understanding the underlying formula is key to arriving at the correct answer below:
From Coulomb's Law, $F = \frac{1}{4\pi\epsilon_0} \frac{q_1 q_2}{r^2}$. Rearranging gives $\epsilon_0 = \frac{q_1 q_2}{4\pi F r^2}$. The unit is $\text{Coulomb}^2/\text{Newton metre}^2$.
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