Match Column – Electrostatics – Rankers Physics

Gauss's Law: Practice Problem & Solution

Match column I and Column II. **Column I**(A) Coulomb's lawn(B) Surface charge density (C) Quantisation of charge (D) Electric flux **Column II**(P) Charge/Area (Q) \( \oint \vec{E} \cdot d\vec{s} \) (R) \( q = ne \) (S) Force is inversely proportional to square of distance
A \( \rightarrow \) P, B \( \rightarrow \) Q, C \( \rightarrow \) R, D \( \rightarrow \) S
A \( \rightarrow \) S, B \( \rightarrow \) P, C \( \rightarrow \) R, D \( \rightarrow \) Q
A \( \rightarrow \) S, B \( \rightarrow \) R, C \( \rightarrow \) P, D \( \rightarrow \) Q
A \( \rightarrow \) S, B \( \rightarrow \) P, C \( \rightarrow \) Q, D \( \rightarrow \) R

Solution Explained:

To solve this problem, we apply the core principles of Gauss's Law. Understanding the underlying formula is key to arriving at the correct answer below:

Coulomb's law is an inverse square law (A-S). Surface charge density is charge per unit area (B-P). Charge is quantised as \( q=ne \) (C-R). Electric flux is defined by Gauss's integral (D-Q).

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