Modified Ampere Circuital Law – Rankers Physics

Ampere's Law and Displacement Current: Practice Problem & Solution

Modified ampere circuital law is given by (symbols have their usual meaning)
\(\oint \vec{B} \cdot d\vec{l} = 0\)
\(\oint \vec{B} \cdot d\vec{l} = \mu_0 I_C\)
\(\oint \vec{B} \cdot d\vec{l} = \mu_0(I_C + I_D)\)
\(\oint \vec{B} \cdot d\vec{l} = \mu_0 I_D\)

Solution Explained:

To solve this problem, we apply the core principles of Ampere's Law and Displacement Current. Understanding the underlying formula is key to arriving at the correct answer below:

The generalized Ampere's circuital law (or Ampere-Maxwell law) includes both conduction current \(I_C\) and displacement current \(I_D\) as sources of magnetic fields, expressed as \(\oint \vec{B} \cdot d\vec{l} = \mu_0(I_C + I_D)\).

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