Power of Electrical Circuit: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Power of Electrical Circuit. Understanding the underlying formula is key to arriving at the correct answer below:

In a series circuit, the current \( I \) is the same for all components. The power dissipated by a bulb is given by \( P = I^2 R \). A lower power bulb has a higher resistance \( (R = V^2/P) \). Thus, it dissipates more power and glows brighter in series. Reason (R) is false because the current is the same for all bulbs in series.