Rankers Physics

Combination of Resistors: Practice Problem & Solution

Two solid conductors are made up of same material have same length and same resistance. One of them has a circular cross section of area $A_{1}$ and the other one has a square cross section of area $A_{2}$. The ratio $A_{1}/A_{2}$ is (2020-Covid)
$1$
$0.8$
$2$
$1.5$

Solution Explained:

To solve this problem, we apply the core principles of Combination of Resistors. Understanding the underlying formula is key to arriving at the correct answer below:

Resistance is given by $R = \rho \frac{l}{A}$. Since the material (hence $\rho$), length $l$, and resistance $R$ are the same for both conductors, their cross-sectional areas must be equal. Therefore, $A_{1} = A_{2}$ and the ratio is $1$.

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