Measuring Devices ( Galvanometer, Voltmeter and Ammeter & Meter Bridge ): Practice Problem & Solution
A milli voltmeter of $25 text{ milli volt}$ range is to be converted into an ammeter of $25 text{ ampere}$ range. The value (in ohm) of necessary shunt will be : (2012 Pre)
Solution Explained:
To solve this problem, we apply the core principles of Measuring Devices ( Galvanometer, Voltmeter and Ammeter & Meter Bridge ). Understanding the underlying formula is key to arriving at the correct answer below:
The required shunt is $S = \frac{V_m}{I} = \frac{25 \times 10^{-3} \text{ V}}{25 \text{ A}} = 0.001 \Omega$.
Leave a Reply