Speed on a frictionless banked curve – Rankers Physics

Dynamics of Circular Motion: Practice Problem & Solution

A car of mass \(1000\text{ kg}\) negotiates a banked curve of radius \(90\text{ m}\) on a frictionless road. If the banking angle is \(45^\circ\), the speed of the car is: (2012 Pre)
\(20\text{ m/s}\)
\(30\text{ m/s}\)
\(5\text{ m/s}\)
\(10\text{ m/s}\)

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Dynamics of Circular Motion. Understanding the underlying formula is key to arriving at the correct answer below:

For an ideal frictionless banked curve, the optimum speed is given by \(v = \sqrt{gRtan\theta}\). Given R = 90 m, \(\theta = 45^\circ\), and assuming \(g = 10\text{ m/s}^2\), \(v = \sqrt{10 \times 90 \times tan 45^\circ} = \sqrt{900 \times 1} = 30\text{ m/s}\).

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