Rankers Physics

Dynamics of Circular Motion: Practice Problem & Solution

A car has to move on a level turn of radius (R = 50m). If the coefficient of static friction between tyre and road is µ = 0.2. Find the maximum speed the car can take without skidding is given by :
20 m/s
10 m/s
9.39 m/s
25 m/s

Solution Explained:

To solve this problem, we apply the core principles of Dynamics of Circular Motion. Understanding the underlying formula is key to arriving at the correct answer below:

For safe turning on a horizontal road.

μ = v²/ rg ⇒ v= (μ rg ) 1/2

v = (0.2 × 50 × 10 ) 1/2 = 10 m/s

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. Assertion (A): The work done by the net force on a particle during non-uniform circular motion is not equal to zero. Reason (R): In case of non-uniform circular motion net force and elementary displacement are not perpendicular to each other.  
2. Assertion (A): When an automobile while going too fast around a curve overturns, its inner wheels leave the ground first. Reason (R): The inner wheels are moving in a circle of smaller radius, the maximum permissible velocity for them is less.
3. A particle of mass \(m\) is tied to a string of length \(l\) and whirled into a horizontal plane. If tension in the string is \(T\) then the speed of the particle will be: (1999)
4. When milk is churned, cream gets separated due to: (1999)
5. Two stones of masses m and 2 m are whirled in horizontal circles, the heavier one in a radius r/2 and the lighter one in radius r. The tangential speed of lighter stone is n times that of the value of heavier stone when they experience same centripetal forces. The value of n is :