Rankers Physics

Uniform Circular Motion: Practice Problem & Solution

A stone of mass 1 kg tied to one end of a string 1.0 m long is revolved in a horizontal circle at the rate of 10/π revolution per second. Calculate the tension of the string ?
300 N
400 N
500 N
600 N

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Uniform Circular Motion. Understanding the underlying formula is key to arriving at the correct answer below:

Tension force in the string will provide required centripetal force

T = mω²r= 1× (10/π ×2π)²×1= 400 N

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