Elastic Collision of Identical Balls – Rankers Physics

Collision: Practice Problem & Solution

Two identical balls $A$ and $B$ having velocities of $0.5\text{ m/s}$ and $-0.3\text{ m/s}$ respectively collide elastically in one dimension. The velocities of $B$ and $A$ after the collision respectively will be: (2016, 1998, 1994, 1991)
$-0.3\text{ m/s}$ and $0.5\text{ m/s}$
$0.3\text{ m/s}$ and $0.5\text{ m/s}$
$-0.5\text{ m/s}$ and $0.3\text{ m/s}$
$0.5\text{ m/s}$ and $-0.3\text{ m/s}$

Solution Explained:

To solve this problem, we apply the core principles of Collision. Understanding the underlying formula is key to arriving at the correct answer below:

In an elastic collision between two identical bodies, their velocities are mutually exchanged. Given initial velocities are $u_1 = 0.5\text{ m/s}$ and $u_2 = -0.3\text{ m/s}$. Therefore, after collision, the velocities of $B$ and $A$ become $0.5\text{ m/s}$ and $-0.3\text{ m/s}$ respectively.

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