Perpendicular Collision of Spheres – Rankers Physics

Collision: Practice Problem & Solution

Two spheres $A$ and $B$ of masses $m_1$ and $m_2$ respectively collide. A is at rest initially and B is moving with velocity $v$ along x-axis. After collision B has a velocity $\frac{v}{2}$ in a direction perpendicular to the original direction. The mass A moves after collision in the direction: (2012 Pre)
Same as that of B
Opposite of that of B
$\theta = \tan^{-1}(1/2)$ to the x-axis
$\theta = \tan^{-1}(-1/2)$ to the x-axis

Solution Explained:

To solve this problem, we apply the core principles of Collision. Understanding the underlying formula is key to arriving at the correct answer below:

Using conservation of linear momentum along y-axis, $m_1 v_{1y} = -m_2 (v/2)$. Along x-axis, $m_1 v_{1x} = m_2 v$. The angle with the x-axis is given by $\theta = \tan^{-1}(v_{1y}/v_{1x}) = \tan^{-1}(-1/2)$.

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