Parallel Plate Capacitor Capacitance Change – Rankers Physics

Parallel Plate Capacitor: Practice Problem & Solution

Assertion (A): If the distance between parallel plates of a capacitor is halved and dielectric constant is three times, then the capacitor becomes 6 times. Reason (R): Capacity of a capacitor depends upon the nature of the plate material.  
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Solution Explained:

To solve this problem, we apply the core principles of Parallel Plate Capacitor. Understanding the underlying formula is key to arriving at the correct answer below:

Assertion (A) is true. For a parallel plate capacitor, \( C = \frac{\kappa \epsilon_0 A}{d} \). If ( d to d/2 ) and \( \kappa to 3\kappa \), then \( C' = \frac{3\kappa \epsilon_0 A}{d/2} = 6 \frac{\kappa \epsilon_0 A}{d} = 6C ). Reason (R) is false as capacitance depends on the dielectric medium, not the plate material.

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