Parallel Plate Capacitor: Practice Problem & Solution
The dielectric strength of a medium is \(2\text{ kV mm}^{-1}\). What is the maximum potential difference that can be set up across a \(50 \mu\text{m}\) specimen without puncturing it?
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Parallel Plate Capacitor. Understanding the underlying formula is key to arriving at the correct answer below:
Dielectric strength is the maximum field \(E_{\text{max}} = 2\text{ kV/mm} = 2 \times 10^6\text{ V/m}\). For thickness \(d = 50 \mu\text{m} = 5 \times 10^{-5}\text{ m}\), the maximum potential difference is \(V_{\text{max}} = E_{\text{max}} \times d = 2 \times 10^6 \times 5 \times 10^{-5} = 100\text{ V}\).
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