Capacitor With Dielectrics: Practice Problem & Solution
The plates of a parallel plate capacitor are charged up to 100 volt. A \(2\text{ mm}\) thick dielectric plate is inserted between the plates, then to maintain the same potential difference, the distance between the capacitor plates is increased by \(1.6\text{ mm}\). The dielectric constant of the plate is :
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Capacitor With Dielectrics. Understanding the underlying formula is key to arriving at the correct answer below:
The shift in plate distance to maintain constant potential is given by \(\Delta d = t\left(1 - \frac{1}{K}\right)\) where \(t\) is thickness and \(K\) is dielectric constant. Substituting the values: \(1.6 = 2\left(1 - \frac{1}{K}\right)⇒ 0.8 = 1 - \frac{1}{K} ⇒ K = 5\).
Leave a Reply