Capacitors: Practice Problem & Solution
The energy stored and potential $V$ is in a capacitor of capacity $C$ given by (1996)
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Capacitors. Understanding the underlying formula is key to arriving at the correct answer below:
The work done in charging a capacitor is stored as electrostatic potential energy. $U = \int V dq = \int \frac{q}{C} dq = \frac{Q^{2}}{2C}$. Since $Q = CV$, $U = \frac{1}{2}CV^{2} = \frac{C V^{2}}{2}$.
Leave a Reply