Rankers Physics

Capacitors: Practice Problem & Solution

A parallel plate capacitor has a uniform electric field $E$ in the space between the plates. If the distance between the plates is $d$ and the area of each plate is $A$, the energy stored in the capacitor is: (2021, 2012 Mains, 2011 pre, 2008)
$\varepsilon_{0} E A d$
$\frac{1}{2} \varepsilon_{0} E^{2} A d$
$\frac{E A d}{\varepsilon}$
$\frac{1}{2} \varepsilon_{0} E^{2}$

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Capacitors. Understanding the underlying formula is key to arriving at the correct answer below:

Energy density $u = \frac{1}{2} \varepsilon_{0} E^{2}$. Total energy $U = u \times \text{volume} = \frac{1}{2} \varepsilon_{0} E^{2} A d$.

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