Alternating Current: Practice Problem & Solution
7. A small signal voltage $V(t) = V_0 \sin \omega t$ is applied across an ideal capacitor C : (2016 - I)
Solution Explained:
To solve this problem, we apply the core principles of Alternating Current. Understanding the underlying formula is key to arriving at the correct answer below:
For an ideal capacitor, the phase difference between current and voltage is $\phi = 90^\circ$ (current leads voltage). The average power consumed over a full cycle is $P_{avg} = V_{rms} I_{rms} \cos(90^\circ) = 0$. Since average power is zero, the capacitor does not consume any energy from the voltage source over a complete cycle.
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