Rankers Physics

Alternating Current: Practice Problem & Solution

1. The peak voltage of the ac source is equal to (2022)
$\frac{1}{\sqrt{2}}$ times the rms value of the source
the value of voltage supplied to the circuit
the rms value of the ac source
$\sqrt{2}$ times the rms value of the ac source

Solution Explained:

To solve this problem, we apply the core principles of Alternating Current. Understanding the underlying formula is key to arriving at the correct answer below:

The root-mean-square (rms) voltage for a sinusoidal alternating voltage is given by $V_{rms} = \frac{V_0}{\sqrt{2}}$. Rearranging for peak voltage $V_0$, we get $V_0 = \sqrt{2} V_{rms}$. Hence, the peak voltage is $\sqrt{2}$ times the rms value of the ac source.

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