Alternating Current: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Alternating Current. Understanding the underlying formula is key to arriving at the correct answer below:

Peak voltage is $E_0 = 200\sqrt{2} V$, so $E_{rms} = \frac{E_0}{\sqrt{2}} = 200 V$. Capacitive reactance is $X_C = \frac{1}{\omega C} = \frac{1}{100 \times 10^{-6}} = 10^4 \Omega$. The rms current is $I_{rms} = \frac{E_{rms}}{X_C} = \frac{200}{10^4} = 20 \times 10^{-3} A = 20 mA$.