Rankers Physics

Capacitors: Practice Problem & Solution

Three capacitors each of capacity $4 \mu F$ are to be connected in such a way that the effective capacitance is $6 \mu F$. This can be done by: (2003)
Connecting all of them in series
Connecting them in parallel
Connecting two in series and one in parallel
Connecting two in parallel and one in series

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Capacitors. Understanding the underlying formula is key to arriving at the correct answer below:

Connecting two $4 \mu F$ capacitors in series gives an equivalent capacitance of $2 \mu F$. Adding the third $4 \mu F$ capacitor in parallel gives a total of $2 \mu F + 4 \mu F = 6 \mu F$.

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