Rankers Physics

Capacitors: Practice Problem & Solution

Three capacitors each of capacitance $C$ and of breakdown voltage $V$ are joined in series. The capacitance and breakdown voltage of the combination will be: (2009)
$3C, \frac{V}{3}$
$\frac{C}{3}, 3V$
$3C, 3V$
$\frac{C}{3}, \frac{V}{3}$

Solution Explained:

To solve this problem, we apply the core principles of Capacitors. Understanding the underlying formula is key to arriving at the correct answer below:

For $3$ identical capacitors in series, the equivalent capacitance is $C_{eq} = \frac{C}{3}$. The breakdown voltages add up, so the total breakdown voltage is $V + V + V = 3V$.

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