Rankers Physics

Capacitors: Practice Problem & Solution

A hollow metallic sphere of radius $10 \text{ cm}$ is charged such that potential of its surface is $80 \text{ V}$. The potential at the centre of the sphere would be (1994)
$80 \text{ V}$
$800 \text{ V}$
Zero
$8 \text{ V}$

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Capacitors. Understanding the underlying formula is key to arriving at the correct answer below:

The electric potential inside a hollow conducting sphere is constant everywhere and is equal to the potential on its surface. Therefore, the potential at the centre is also $80 \text{ V}$.

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. A battery is used to charge a parallel-plate capacitor, after which it is disconnected. Then the plates are pulled apart to twice their original separation. This process will double the :
2. A capacitor of capacitance C is connected across a battery of potential difference V. Assertion (A): The energy stored in capacitor is \( \frac{1}{2} CV^2 \). Reason (R): The energy supplied by the battery is \( CV^2 \).  
3. Choose the CORRECT statement :
4. A series combination of $n_{1}$ capacitors, each of value $C_{1}$, is charged by a source of potential difference $4V$. When another parallel combination of $n_{2}$ capacitors, each of value $C_{2}$, is charged by a source of potential difference $V$, it has the same (total) energy stored in it, as the first combination has. The value of $C_{2}$, in terms of $C_{1}$, is then: (2010 Pre)
5. Three capacitors each of capacitance $C$ and of breakdown voltage $V$ are joined in series. The capacitance and breakdown voltage of the combination will be: (2009)