Solution:
Thermal conductivity $K = frac{Delta Q cdot x}{A cdot Delta T cdot t}$
Unit $= frac{text{J} cdot text{m}}{text{m}^2 cdot text{K} cdot text{s}} = frac{text{W}}{text{m K}} = text{W m}^{-1} text{K}^{-1}$
Thermal conductivity $K = frac{Delta Q cdot x}{A cdot Delta T cdot t}$
Unit $= frac{text{J} cdot text{m}}{text{m}^2 cdot text{K} cdot text{s}} = frac{text{W}}{text{m K}} = text{W m}^{-1} text{K}^{-1}$
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