First Law of Thermodynamics in Isobaric Process – Rankers Physics

Thermodynamics: Practice Problem & Solution

For $n$ mole of an ideal gas, the correct equation of $1^{\text{st}}$ law of thermodynamics corresponding to isobaric process will be (symbols have their usual meanings)
$Q = \Delta U + P\Delta V$
$Q = \Delta U + nR\Delta T$
$Q = \Delta U$
Both (1) and (2)

Solution Explained:

To solve this problem, we apply the core principles of Thermodynamics. Understanding the underlying formula is key to arriving at the correct answer below:

By first law, $Q = \Delta U + W$. In an isobaric process, the work done is $W = P\Delta V = nR\Delta T$. Therefore, both expressions are correct.

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