Impulse-momentum theorem – Rankers Physics

Uncategorized: Practice Problem & Solution

A particle of mass \(m\) is moving with a uniform velocity \(v_1\). It is given an impulse such that its velocity becomes \(v_2\). The impulse is equal to: (1990)
\(m|v_2| - |v_1|\)
\(frac{1}{2}m[v_2^2 - v_1^2]\)
\(m[v_1 + v_2]\)
\(m[v_2 - v_1]\)

Solution Explained:

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

Impulse is defined as the change in momentum of an object. If the initial momentum is \(p_1 = mv_1\) and the final momentum is \(p_2 = mv_2\), then the impulse is \(I = p_2 - p_1 = m(v_2 - v_1)\).

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