First Law of Thermodynamics in Isobaric Process – Rankers Physics

Thermodynamics: Practice Problem & Solution

For $n$ mole of an ideal gas, the correct equation of $1^{\text{st}}$ law of thermodynamics corresponding to isobaric process will be (symbols have their usual meanings)
$Q = \Delta U + P\Delta V$
$Q = \Delta U + nR\Delta T$
$Q = \Delta U$
Both (1) and (2)

Solution Explained:

To solve this problem, we apply the core principles of Thermodynamics. Understanding the underlying formula is key to arriving at the correct answer below:

By first law, $Q = \Delta U + W$. In an isobaric process, the work done is $W = P\Delta V = nR\Delta T$. Therefore, both expressions are correct.

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. Assertion (A): The ratio \( \frac{C_P}{C_V} \) is more for helium gas than for hydrogen gas. Reason (R): Atomic mass of helium is more than that of hydrogen.  
2. At 10°C the value of the density of a fixed mass of an ideal gas divided by its pressure is X. At 110°C this ratio is
3. Assertion (A): In an ideal monoatomic gas, The Internal energy of gas is equal to translational Kinetic energy of all its molecules Reason (R): The Internal energy may get contributes from Translational, Rotatory, vibrationally as well as from the Potential energy corresponding to the molecular force.  
4. Assertion (A): Work done by a gas in isothermal expansion is more than the work done by the gas in the same expansion adiabatically. Reason (R): Temperature remains constant in isothermal expansion but not in adiabatic expansion.  
5. In ideal condition, the maximum efficiency that can be derived from a heat engine built operating between \(600\text{ K}\) reservoir and \(200\text{ K}\) sink, is