Work Done by Constant and Variable Forces: Practice Problem & Solution
A body moves a distance of \(10\text{ m} \) along a straight line under the action of a \(5\text{ N}\) force. If the work done is \(25\text{ J}\), then the angle between the force and direction of motion of the body is (1997)
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Work Done by Constant and Variable Forces. Understanding the underlying formula is key to arriving at the correct answer below:
Work \(W = Fd cos\theta\). Given \(W = 25\text{ J}\), \(F = 5\text{ N}\), \(d = 10\text{ m})\). \(25 = (5)(10) cos\theta\). \(cos\theta = \frac{1}{2}\). Therefore, \(\theta = 60^{\circ}\).
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