Power and Water Pump Output – Rankers Physics

Power: Practice Problem & Solution

The power of a water pump is \(100 \text{kW}\). If \(g = 10 \text{m/s}^2\), then the amount of water it can raise in \(2 \text{s}\) to a height of \(20 \text{m}\) is
\(200 \text{kg}\)
\(300 \text{kg}\)
\(400 \text{kg}\)
\(1000 \text{kg}\)

Solution Explained:

To solve this problem, we apply the core principles of Power. Understanding the underlying formula is key to arriving at the correct answer below:

Power \(P = \frac{mgh}{t} ⇒ 100 \times 10^3 = \frac{m \times 10 \times 20}{2}\). This simplifies to \(100 \times 10^3 = 100 m ⇒ m = 1000 \text{kg}\).

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